3x^2=104

Solution for 3x^2=104 equation:

3x^2=104

We move all terms to the left:

3x^2-(104)=0

a = 3; b = 0; c = -104;
Δ = b2-4ac
Δ = 02-4·3·(-104)
Δ = 1248
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1248}=\sqrt{16*78}=\sqrt{16}*\sqrt{78}=4\sqrt{78}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{78}}{2*3}=\frac{0-4\sqrt{78}}{6}
=-\frac{4\sqrt{78}}{6}
=-\frac{2\sqrt{78}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{78}}{2*3}=\frac{0+4\sqrt{78}}{6}
=\frac{4\sqrt{78}}{6}
=\frac{2\sqrt{78}}{3}
$